What does the insertion code p->link = new nodeType{50, p->link}; accomplish?

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Multiple Choice

What does the insertion code p->link = new nodeType{50, p->link}; accomplish?

Explanation:
Inserting after a specific node in a singly linked list is what this line does. It creates a new node with the value 50 and its next pointer set to what p was already pointing to (the node that followed p). Then it updates p’s next pointer to point to this new node. So the new node sits between p and the old successor, preserving the rest of the list. This does not change p’s data, delete any node, or make p null.

Inserting after a specific node in a singly linked list is what this line does. It creates a new node with the value 50 and its next pointer set to what p was already pointing to (the node that followed p). Then it updates p’s next pointer to point to this new node. So the new node sits between p and the old successor, preserving the rest of the list. This does not change p’s data, delete any node, or make p null.

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